Magnetic Properties
The magnetic moment (spin-only) of [Fe(CN)6]4− is approximately:
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Solution
0 BM
For [Fe(CN)6]4−, oxidation state of Fe is +2, so Fe2+ is d6. CN− is a strong field ligand, causing pairing in t2g orbitals for octahedral low-spin d6: t2g6 eg0. Number of unpaired electrons is zero, so spin-only magnetic moment is 0 BM.
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About This Question
- Subject
- chemistry
- Chapter
- coordination compounds
- Topic
- magnetic properties
- Difficulty
- Medium
- Year
- 2025
Solution
Correct Answer:
0 BM
For [Fe(CN)6]4−, oxidation state of Fe is +2, so Fe2+ is d6. CN− is a strong field ligand, causing pairing in t2g orbitals for octahedral low-spin d6: t2g6 eg0. Number of unpaired electrons is zero, so spin-only magnetic moment is 0 BM.
This medium difficulty chemistry question is from the chapter coordination compounds, covering the topic of magnetic properties. It appeared in the 2025 exam.
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