Magnetic Properties

Question

The magnetic moment of [Fe(CN)₆]⁴⁻ ion is:

RankGuru · Accepted Answer

1. **Identify the metal ion**: In $[Fe(CN)_6]^{4-}$, primary valence of $Fe$ is $+2$. $Fe^{2+}$ is **$3d^6$**.
2. **Ligand Nature**: $CN^-$ is a **strong-field ligand**.
3. **Splitting**: Strong-field ligands cause the electrons to pair up in the lower $t_{2g}$ orbitals before filling $e_g$.
- $t_{2g}^6 \, e_g^0$: All $6$ electrons are paired.
4. **Magnetic Moment**: Number of unpaired electrons ($n$) = $0$.
- Formula: $\mu = \sqrt{n(n+2)} = 0 	ext{ BM}$.
- The complex is **diamagnetic**.

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