Magnetic Properties

Electronic State: $F e^{2 +}$ has a $d^{6}$ configuration.
Ligand Field: $C N^{-}$ is a very strong field ligand (High splitting, $Δ_{o} >> P$ ).
Filling Pattern: To avoid the high energy of the $e_{g}$ orbitals, all six electrons fill and pair up in the lower $t_{2 g}$ orbitals ( $t_{2 g}^{6} e_{g}^{0}$ ).
Observations: Since all electrons are paired, there is no net magnetic moment.
Conclusion: The complex is diamagnetic.

This medium difficulty chemistry question is from the chapter coordination compounds, covering the topic of magnetic properties. It appeared in the 2025 exam.

Looking for more practice? Explore all chemistry questions or browse coordination compounds questions on RankGuru.

Magnetic Properties

Select the correct option:

🔒 Solution Hidden from View

More coordination compounds Practice Questions

The spin-only magnetic moment of a d5 high-spin ion is closest to:

The magnetic moment (spin-only) of [Fe(CN)6]4− is approximately:

Paramagnetism in transition metal ions is due to:

The magnetic moment of [Fe(CN)₆]⁴⁻ ion is:

The metal-carbon bond in metal carbonyls is unusually strong because of an additional interaction be...

The oxygen-carrying pigment haemoglobin owes its function to a coordination complex; which central m...

Inside the complex anion present in potassium hexafluoridocobaltate, what is the oxidation state of ...

A complex containing the bidentate ligand ethylenediamine is more stable than the comparable complex...

An aqueous solution of a titanium(III) complex appears purple because the single d electron absorbs ...

When the same metal ion binds a weak-field ligand instead of a strong-field ligand in an octahedral ...

A central metal ion is surrounded by four ligands and the complex is found to be diamagnetic with a ...

For the neutral carbonyl complex of nickel, [Ni(CO)4], what is the effective atomic number of the ce...

About This Question

Solution