Magnetic Properties

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[Fe(CN)6]4− magnetic character is best described as:

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Paramagnetic with 2 unpaired electrons

Paramagnetic with 4 unpaired electrons

Diamagnetic

Ferromagnetic

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About This Question

Subject: chemistry
Chapter: coordination compounds
Topic: magnetic properties
Difficulty: Medium
Year: 2025

Solution

Correct Answer:

Diamagnetic

Electronic State: $F e^{2 +}$ has a $d^{6}$ configuration.
Ligand Field: $C N^{-}$ is a very strong field ligand (High splitting, $Δ_{o} >> P$ ).
Filling Pattern: To avoid the high energy of the $e_{g}$ orbitals, all six electrons fill and pair up in the lower $t_{2 g}$ orbitals ( $t_{2 g}^{6} e_{g}^{0}$ ).
Observations: Since all electrons are paired, there is no net magnetic moment.
Conclusion: The complex is diamagnetic.

This medium difficulty chemistry question is from the chapter coordination compounds, covering the topic of magnetic properties. It appeared in the 2025 exam.

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Magnetic Properties

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More magnetic properties Practice Questions

The spin-only magnetic moment of a d5 high-spin ion is closest to:

The magnetic moment (spin-only) of [Fe(CN)6]4− is approximately:

Paramagnetism in transition metal ions is due to:

The magnetic moment of [Fe(CN)₆]⁴⁻ ion is:

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