High Spin And Low Spin
When the same metal ion binds a weak-field ligand instead of a strong-field ligand in an octahedral complex, how does the number of unpaired electrons usually change?
Select the correct option:
Solution
It increases because weak fields favour the high-spin arrangement
Whether an octahedral complex is high spin or low spin depends on the competition between the crystal field splitting energy and the electron pairing energy. A weak-field ligand produces a small splitting, so it is energetically cheaper for electrons to occupy the higher e_g orbitals singly than to pair up in the lower t_{2g} set. This gives the high-spin configuration with the maximum number of unpaired electrons. A strong-field ligand produces a large splitting that exceeds the pairing energy, so electrons pair in t_{2g} first, giving the low-spin arrangement with fewer unpaired electrons. Therefore switching from a strong-field to a weak-field ligand generally increases the number of unpaired electrons. The option that the count never changes ignores the field-strength dependence. The option that weak fields force pairing reverses the correct logic. Reaching zero unpaired electrons is a low-spin, not weak-field, outcome. This balance is the core NCERT criterion for spin state. Plausibility check: weak-field [CoF6]^{3-} is paramagnetic while strong-field [Co(NH3)6]^{3+} is diamagnetic, exactly matching the predicted increase in unpaired electrons.
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About This Question
- Subject
- chemistry
- Chapter
- coordination compounds
- Topic
- high spin and low spin
- Difficulty
- Hard
- Year
- 2025
Solution
Correct Answer:
It increases because weak fields favour the high-spin arrangement
Whether an octahedral complex is high spin or low spin depends on the competition between the crystal field splitting energy and the electron pairing energy. A weak-field ligand produces a small splitting, so it is energetically cheaper for electrons to occupy the higher e_g orbitals singly than to pair up in the lower t_{2g} set. This gives the high-spin configuration with the maximum number of unpaired electrons. A strong-field ligand produces a large splitting that exceeds the pairing energy, so electrons pair in t_{2g} first, giving the low-spin arrangement with fewer unpaired electrons. Therefore switching from a strong-field to a weak-field ligand generally increases the number of unpaired electrons. The option that the count never changes ignores the field-strength dependence. The option that weak fields force pairing reverses the correct logic. Reaching zero unpaired electrons is a low-spin, not weak-field, outcome. This balance is the core NCERT criterion for spin state. Plausibility check: weak-field [CoF6]^{3-} is paramagnetic while strong-field [Co(NH3)6]^{3+} is diamagnetic, exactly matching the predicted increase in unpaired electrons.
This hard difficulty chemistry question is from the chapter coordination compounds, covering the topic of high spin and low spin. It appeared in the 2025 exam.
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