Ozonolysis Identification

Ozonolysis Reaction: $A l k e n es + O_{3} \to O z u ni d e Z n / H_{2} O Carbonyl Compounds$ .
Visual Logic: Simply 'cut' the double bond and place an Oxygen atom at each end of the fragments.
Analyzing Options:
- But-2-ene ( $C H_{3} - C H = C H - C H_{3}$ ): Symmetrical cleavage yields $C H_{3} C H O$ and $C H_{3} C H O$ (two ethanal molecules).
- But-1-ene ( $C H_{3} - C H_{2} - C H = C H_{2}$ ): Yields Propanal ( $C H_{3} C H_{2} C H O$ ) and Methanal ( $H C H O$ ).
- 2-Methylprop-1-ene ( $(C H_{3})_{2} C = C H_{2}$ ): Yields Acetone ( $(C H_{3})_{2} C = O$ ) and Methanal.
- Ethene ( $C H_{2} = C H_{2}$ ): Yields two Methanal molecules.
Conclusion: Only But-2-ene satisfies the condition.

This medium difficulty chemistry question is from the chapter hydrocarbons, covering the topic of ozonolysis identification. It appeared in the 2025 exam.

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Ozonolysis Identification

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