Stereochemistry Of Electrophilic Addition
Bromine adds to cyclohexene to form a dibromide, and the stereochemical relationship between the two newly introduced bromine atoms must be described accurately.
Select the correct option:
Solution
Thetwobromineatomsaddinatrans(anti)fashionacrossthering
Electrophilic addition of Br2 to an alkene proceeds through a cyclic bromonium ion intermediate rather than an open carbocation, and this intermediate controls the stereochemistry. When Br2 approaches cyclohexene, one bromine forms a three-membered bromonium ring bridging both alkene carbons, blocking one face of the molecule. The liberated bromide ion then attacks a carbon from the opposite face, a backside SN2-like attack, so the second bromine adds anti to the first. The result is trans-1,2-dibromocyclohexane, with the two bromines on opposite faces. The cis option is wrong because syn addition would require both bromines to approach the same face, which the bromonium mechanism forbids. The option placing both bromines on one carbon is incorrect because addition occurs across the double bond, one bromine per carbon. The claim of non-stereospecific random addition is false; the bromonium ion makes the reaction strictly anti and therefore stereospecific. The bromonium intermediate is favoured over an open carbocation because bromine's lone pairs can bridge the two carbons, distributing the positive charge and avoiding a high-energy localised cation. This bridged geometry is precisely what forces the incoming bromide to approach from the side opposite the bromonium, sealing the anti outcome. This is the NCERT-supported mechanism of halogen addition to alkenes. A consistency check: opening a bridged bromonium ion by backside attack must give anti products, confirming the trans dibromide.
🔒 Solution Hidden from View
Submit your answer to unlock the detailed step-by-step solution.
About This Question
- Subject
- chemistry
- Chapter
- hydrocarbons
- Topic
- stereochemistry of electrophilic addition
- Difficulty
- Hard
- Year
- 2025
Solution
Correct Answer:
Thetwobromineatomsaddinatrans(anti)fashionacrossthering
Electrophilic addition of Br2 to an alkene proceeds through a cyclic bromonium ion intermediate rather than an open carbocation, and this intermediate controls the stereochemistry. When Br2 approaches cyclohexene, one bromine forms a three-membered bromonium ring bridging both alkene carbons, blocking one face of the molecule. The liberated bromide ion then attacks a carbon from the opposite face, a backside SN2-like attack, so the second bromine adds anti to the first. The result is trans-1,2-dibromocyclohexane, with the two bromines on opposite faces. The cis option is wrong because syn addition would require both bromines to approach the same face, which the bromonium mechanism forbids. The option placing both bromines on one carbon is incorrect because addition occurs across the double bond, one bromine per carbon. The claim of non-stereospecific random addition is false; the bromonium ion makes the reaction strictly anti and therefore stereospecific. The bromonium intermediate is favoured over an open carbocation because bromine's lone pairs can bridge the two carbons, distributing the positive charge and avoiding a high-energy localised cation. This bridged geometry is precisely what forces the incoming bromide to approach from the side opposite the bromonium, sealing the anti outcome. This is the NCERT-supported mechanism of halogen addition to alkenes. A consistency check: opening a bridged bromonium ion by backside attack must give anti products, confirming the trans dibromide.
This hard difficulty chemistry question is from the chapter hydrocarbons, covering the topic of stereochemistry of electrophilic addition. It appeared in the 2025 exam.
Looking for more practice? Explore all chemistry questions or browse hydrocarbons questions on RankGuru.