Aromaticity And Huckel Rule
A planar cyclic conjugated species is being assessed for aromatic character, and the number of delocalised pi electrons required by the Huckel criterion must be stated correctly.
Select the correct option:
Solution
A count satisfying (4n+2) pi electrons such as 2, 6, or 10
Aromaticity requires that a species be cyclic, planar, fully conjugated around the ring, and contain a specific number of delocalised pi electrons given by Huckel's rule, namely (4n+2) where n is a non-negative integer. Substituting n=0,1,2 gives allowed counts of 2,6,10 pi electrons, which is why benzene with six pi electrons is the archetypal aromatic compound. The option specifying 4n electrons such as 4,8,12 is wrong because those counts correspond to antiaromatic systems, which are actually destabilized, like cyclobutadiene. The option allowing any even number is incorrect because 4n even counts are not aromatic, so evenness alone is insufficient. The claim of exactly eight pi electrons is false since eight equals 4n and would be antiaromatic, not aromatic. The rule also requires planarity and continuous overlap, which is why non-planar or non-conjugated rings are not aromatic even with the right electron count. The physical basis of the rule lies in molecular orbital theory: a (4n+2) count exactly fills all the bonding molecular orbitals of the cyclic pi system, giving a closed-shell, low-energy arrangement, whereas a 4n count leaves two electrons in non-bonding or partially filled orbitals and is destabilised. This is the NCERT and JEE statement of Huckel's rule applied to cyclic conjugated systems. A plausibility check: benzene's six pi electrons fit (4n+2) with n=1, anchoring the rule.
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About This Question
- Subject
- chemistry
- Chapter
- hydrocarbons
- Topic
- aromaticity and huckel rule
- Difficulty
- Medium
- Year
- 2025
Solution
Correct Answer:
A count satisfying (4n+2) pi electrons such as 2, 6, or 10
Aromaticity requires that a species be cyclic, planar, fully conjugated around the ring, and contain a specific number of delocalised pi electrons given by Huckel's rule, namely (4n+2) where n is a non-negative integer. Substituting n=0,1,2 gives allowed counts of 2,6,10 pi electrons, which is why benzene with six pi electrons is the archetypal aromatic compound. The option specifying 4n electrons such as 4,8,12 is wrong because those counts correspond to antiaromatic systems, which are actually destabilized, like cyclobutadiene. The option allowing any even number is incorrect because 4n even counts are not aromatic, so evenness alone is insufficient. The claim of exactly eight pi electrons is false since eight equals 4n and would be antiaromatic, not aromatic. The rule also requires planarity and continuous overlap, which is why non-planar or non-conjugated rings are not aromatic even with the right electron count. The physical basis of the rule lies in molecular orbital theory: a (4n+2) count exactly fills all the bonding molecular orbitals of the cyclic pi system, giving a closed-shell, low-energy arrangement, whereas a 4n count leaves two electrons in non-bonding or partially filled orbitals and is destabilised. This is the NCERT and JEE statement of Huckel's rule applied to cyclic conjugated systems. A plausibility check: benzene's six pi electrons fit (4n+2) with n=1, anchoring the rule.
This medium difficulty chemistry question is from the chapter hydrocarbons, covering the topic of aromaticity and huckel rule. It appeared in the 2025 exam.
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