Potassium Permanganate
When potassium permanganate acts as an oxidising agent in acidic medium, to which oxidation state is the manganese reduced from its initial plus seven state?
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About This Question
- Subject
- chemistry
- Chapter
- d- and f-block elements
- Topic
- potassium permanganate
- Difficulty
- Easy
- Year
- 2025
Solution
Correct Answer:
+2
The product of permanganate reduction depends on the medium of the reaction. In acidic medium, the permanganate ion MnO_4^-, in which manganese is in the +7 state, is reduced by gaining five electrons to give the nearly colourless Mn^2+ ion, in which manganese is in the +2 state: MnO_4^- + 8H^+ + 5e^- → Mn^2+ + 4H_2O. This five-electron change makes permanganate a powerful oxidant in acidic conditions. The option +3 is not a stable reduction product of permanganate in acid. The option +4 corresponds to MnO_2, which forms in neutral or faintly alkaline medium. The option +6 corresponds to the green manganate ion MnO_4^2-, formed in strongly alkaline medium. Knowing the medium-dependent products of permanganate is a standard NCERT d-block fact essential for redox titrations. Plausibility check: the disappearance of the purple colour to give almost colourless Mn^2+ in acidic titrations confirms reduction to the +2 state.
This easy difficulty chemistry question is from the chapter d- and f-block elements, covering the topic of potassium permanganate. It appeared in the 2025 exam.
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