Skip to content

General Properties Of F-block

Easychemistry

The most common and stable oxidation state shown by the majority of the lanthanoid elements in their compounds is which of the following?

Select the correct option:

🔒 Solution Hidden from View

Submit your answer to unlock the detailed step-by-step solution.

About This Question

Subject
chemistry
Chapter
d- and f-block elements
Topic
general properties of f-block
Difficulty
Easy
Year
2025
Tags
lanthanoidscommon oxidation state+3 state4f shieldingf-block property

Solution

Correct Answer:

The lanthanoids are characterised by a strong preference for a single common oxidation state. The most stable and characteristic oxidation state of the majority of lanthanoid elements is +3, formed by the loss of the two 6s electrons and one 4f or 5d electron. This +3 state is stable because the deeply buried 4f electrons are well shielded and reluctant to take part in further bonding, so most lanthanoids form M^3+ ions and compounds such as their oxides and chlorides. A few lanthanoids show +2 or +4 states in special cases, such as Eu^2+ and Ce^4+, where these confer extra stability through half-filled or empty f-subshells, but +3 dominates. The option +1 is not a characteristic state. The option +2 occurs only exceptionally. The option +4 is also exceptional and not the general state. The dominance of the +3 state is a fundamental NCERT f-block fact. Plausibility check: the formation of M^3+ oxides and salts by nearly all lanthanoids confirms that +3 is the common stable oxidation state.

This easy difficulty chemistry question is from the chapter d- and f-block elements, covering the topic of general properties of f-block. It appeared in the 2025 exam.

Looking for more practice? Explore all chemistry questions or browse d- and f-block elements questions on RankGuru.