Standard Electrode Potential Anomaly
The standard reduction potential of the Mn^3+/Mn^2+ couple is unusually high and positive; what electronic factor explains this strong tendency to be reduced?
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About This Question
- Subject
- chemistry
- Chapter
- d- and f-block elements
- Topic
- standard electrode potential anomaly
- Difficulty
- Hard
- Year
- 2025
Solution
Correct Answer:
Reductiongivesthestablehalf−filled3d5configurationofMn2+
The unusually high positive reduction potential of the Mn^3+/Mn^2+ couple reflects the special stability gained on reduction. Manganese(III) has the configuration 3d^4, while manganese(II) has the configuration 3d^5, an exactly half-filled d-subshell that is especially stable because of its symmetrical electron distribution and favourable exchange energy. The strong drive to reach this stable half-filled configuration makes Mn^3+ readily accept an electron to become Mn^2+, giving a large positive reduction potential and making Mn^3+ a strong oxidising agent. The option that Mn^2+ has an unstable configuration is the opposite of the truth. The option that Mn^3+ is already very stable contradicts its tendency to be reduced. The option that manganese has no d-electrons is false. This thermodynamic anomaly tied to half-filled stability is a key JEE Advanced concept. Such questions reward conceptual clarity, since a student who truly grasps electrode potential anomaly can solve many superficially different variants with the same approach. Examiners frequently test whether a student can connect Mn3+/Mn2+ couple with the underlying principle rather than merely recalling an isolated fact. Plausibility check: the strong oxidising behaviour of Mn^3+, which disproportionates readily to Mn^2+ and MnO_2, confirms the driving force toward the stable 3d^5 configuration.
This hard difficulty chemistry question is from the chapter d- and f-block elements, covering the topic of standard electrode potential anomaly. It appeared in the 2025 exam.
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