Impedance Rlc Hard
Hardphysics
Magnitude of impedance Z of series RLC at angular frequency ω is:
Select the correct option:
Solution
Incorrect! Answer:
√(R2+(ωL−1/(ωC))2)
In a series RLC circuit, the total opposition to AC flow is Impedance (Z). Using the phasor diagram:
- VR is in phase with I.
- VL leads I by 90∘.
- VC lags I by 90∘. Total reactive component: X=XL−XC=ωL−ωC1. Combining with resistance R (at 90∘ to reactance): Z=R2+X2=R2+(ωL−ωC1)2.
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About This Question
- Subject
- physics
- Chapter
- electromagnetic induction and ac
- Topic
- impedance rlc hard
- Difficulty
- Hard
- Year
- 2025
Solution
Correct Answer:
√(R2+(ωL−1/(ωC))2)
In a series RLC circuit, the total opposition to AC flow is Impedance (Z). Using the phasor diagram:
- VR is in phase with I.
- VL leads I by 90∘.
- VC lags I by 90∘. Total reactive component: X=XL−XC=ωL−ωC1. Combining with resistance R (at 90∘ to reactance): Z=R2+X2=R2+(ωL−ωC1)2.
This hard difficulty physics question is from the chapter electromagnetic induction and ac, covering the topic of impedance rlc hard. It appeared in the 2025 exam.
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