transformer ideal

Question

Ideal transformer voltage ratio equals turns ratio V2/V1 =:

RankGuru · Accepted Answer

In an ideal transformer (no flux leakage, zero resistance), the EMF induced in each turn is the same ($e = -d\phi/dt$).
- Primary voltage: $V_1 = N_1 e$
- Secondary voltage: $V_2 = N_2 e$
- Ratio: $\frac{V_2}{V_1} = \frac{N_2}{N_1}$
Also, from power conservation ($V_1 I_1 = V_2 I_2$), the current ratio is the inverse: $\frac{I_2}{I_1} = \frac{N_1}{N_2}$.

Rank Guru

transformer ideal

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