Kinetic energy associated with pure rotation is analogous to translational kinetic energy ($K_{trans}=\frac{1}{2}m{v}^2$). Replacing mass $m$ with moment of inertia $I$ and linear speed $v$ with angular speed $\omega$: $K_{rot}=\frac{1}{2}I{\omega }^2$

• SI Unit: Joules ($J$).
• For a rolling object, the total kinetic energy is the sum of translational and rotational components.