rotational kinetic energy

Question

A flywheel (I = 5 kg·m²) rotates at 8 rad/s. Rotational kinetic energy?

RankGuru · Accepted Answer

1. **Energy Formula**: The kinetic energy of a purely rotating object is $K_{rot} = \frac{1}{2} I \omega^2$.
2. **Identify Variables**:
   - $I = 5 	ext{ kg·m}^2$
   - $\omega = 8 	ext{ rad/s}$
3. **Calculation**:
   - $K_{rot} = \frac{1}{2} 	imes 5 	imes (8)^2$
   - $K_{rot} = 2.5 	imes 64$
   - $K_{rot} = 160$ J.
4. **Conclusion**: The energy stored in the flywheel is **$160$ J**.

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A flywheel of moment of inertia 4 kg·m² rotates at 5 rad/s. What is its rotational kinetic energy?

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