rotational kinetic energy

Question

A flywheel of moment of inertia 4 kg·m² rotates at 5 rad/s. What is its rotational kinetic energy?

RankGuru · Accepted Answer

1. **Rotational Kinetic Energy Formula**: $K_{rot} = \frac{1}{2} I \omega^2$.
2. **Variables**:
   - $I = 4$ kg·m$^2$.
   - $\omega = 5$ rad/s.
3. **Calculation**:
   - $K_{rot} = \frac{1}{2} 	imes 4 	imes (5)^2 = 2 	imes 25$.
4. **Result**: $K_{rot} = 50$ Joules.
5. **Significance**: This is the energy stored in the rotating body, used in flywheels to smooth out power delivery.

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