Mole Concept
A sample of an oxide of iron contains 7.0 g of iron and 3.0 g of oxygen. If the atomic masses of Fe and O are 56 and 16 respectively, the empirical formula of the oxide is:
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About This Question
- Subject
- chemistry
- Chapter
- some basic concepts in chemistry
- Topic
- mole concept
- Difficulty
- Medium
- Year
- 2025
Solution
Correct Answer:
Fe₂O₃
- Convert Masses to Moles:
- Moles of Fe = 567.0=0.125 mol.
- Moles of O = 163.0=0.1875 mol.
- Find the Simplest Mole Ratio: Divide each by the smallest value (0.125):
- Fe: 0.1250.125=1
- O: 0.1250.1875=1.5
- Convert to Whole Numbers: Multiply both by 2:
- Fe: 1×2=2
- O: 1.5×2=3
- Write the Empirical Formula: Fe2O3.
- Verification: In Fe2O3, the mass ratio is (2×56):(3×16)=112:48=7:3, which matches the given data exactly.
This medium difficulty chemistry question is from the chapter some basic concepts in chemistry, covering the topic of mole concept. It appeared in the 2025 exam.
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