Mole Concept

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When 9.0 g of aluminium reacts completely with oxygen, how many grams of Al2O3 are formed? (2Al + 3/2 O2 → Al2O3, M(Al)=27, M(Al2O3)=102)

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9.0 g

17.0 g

27.0 g

34.0 g

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About This Question

Subject: chemistry
Chapter: some basic concepts in chemistry
Topic: mole concept
Difficulty: Medium
Year: 2025

Solution

Correct Answer:

17.0 g

Reaction Stoichiometry: $2 A l + \frac{3}{2} O_{2} \to A l_{2} O_{3}$ .
- $2 m o l A l \to 1 m o l A l_{2} O_{3}$ .
Find Moles of $A l$ :
- $n_{A l} = \frac{9.0}{27} = \frac{1}{3} m o l$ .
Find Moles of $A l_{2} O_{3}$ produced:
- $n_{y i e l d} = \frac{1}{2} \times \frac{1}{3} = \frac{1}{6} m o l$ .
Calculate Mass:
- $M a ss = \frac{1}{6} \times 102 g / m o l = 17 g$ .

This medium difficulty chemistry question is from the chapter some basic concepts in chemistry, covering the topic of mole concept. It appeared in the 2025 exam.

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