Mole Concept
Determine empirical formula of a compound with 52.17% C, 34.78% O and 13.04% H (Atomic masses: C=12, O=16, H=1).
Select the correct option:
Solution
C2H6O
- Moles in 100g:
- C:52.17/12=4.348 mol.
- H:13.04/1=13.04 mol.
- O:34.78/16=2.174 mol.
- Simplest Ratio (divide by smallest, 2.174):
- C:4.348/2.174=2.
- H:13.04/2.174=6.
- O:2.174/2.174=1.
- Result: Empirical formula is C2H6O.
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About This Question
- Subject
- chemistry
- Chapter
- some basic concepts in chemistry
- Topic
- mole concept
- Difficulty
- Medium
- Year
- 2025
Solution
Correct Answer:
C2H6O
- Moles in 100g:
- C:52.17/12=4.348 mol.
- H:13.04/1=13.04 mol.
- O:34.78/16=2.174 mol.
- Simplest Ratio (divide by smallest, 2.174):
- C:4.348/2.174=2.
- H:13.04/2.174=6.
- O:2.174/2.174=1.
- Result: Empirical formula is C2H6O.
This medium difficulty chemistry question is from the chapter some basic concepts in chemistry, covering the topic of mole concept. It appeared in the 2025 exam.
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