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Limiting Reagent

Easychemistry

In a reaction between nitrogen and hydrogen gases to form ammonia ((\text{N}_2 + 3\text{H}_2 \rightarrow 2\text{NH}_3)), if 2 mol of (\text{N}_2) and 3 mol of (\text{H}_2) are mixed, which substance is the limiting reagent?

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About This Question

Subject
chemistry
Chapter
some basic concepts in chemistry
Topic
limiting reagent
Difficulty
Easy
Year
2025
Tags
limiting reagentstoichiometryHaber processmole ratioreaction yield

Solution

Correct Answer:

\(\text{H}_2\)

The limiting reagent is the reactant that is completely consumed first, thereby determining the maximum yield of product. The balanced equation (\text{N}_2 + 3\text{H}_2 \rightarrow 2\text{NH}_3) shows that 1 mol of (\text{N}_2) reacts with 3 mol of (\text{H}_2). Stoichiometric check: to consume 2 mol of (\text{N}_2), we need (2 \times 3 = 6) mol of (\text{H}_2). But only 3 mol of (\text{H}_2) is available, which is only enough to react with (3/3 = 1) mol of (\text{N}_2). Hence (\text{H}_2) is exhausted first and is the limiting reagent. (\text{N}_2) is incorrect because 1 mol of (\text{N}_2) remains unreacted after all (\text{H}_2) is consumed. (\text{NH}_3) is a product, not a reagent, so it cannot be the limiting reagent. Both cannot be limiting simultaneously in a standard stoichiometric scenario. This is a fundamental NCERT concept on limiting reagents in chemical reactions. Plausibility check: only (2 \times (3/6) = 1) mol (\text{N}_2) is consumed and (2 \times 1 = 2) mol (\text{NH}_3) is produced, confirming (\text{H}_2) is consumed first.

This easy difficulty chemistry question is from the chapter some basic concepts in chemistry, covering the topic of limiting reagent. It appeared in the 2025 exam.

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