Limiting Reagent
10 g of hydrogen reacts with 80 g of oxygen. What is the mass of water formed?
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Solution
90 g
- Equation: 2H2+O2→2H2O
- Moles calculation:
- Moles H2=10/2=5 mol.
- Moles O2=80/32=2.5 mol.
- Stoichiometry check:
- To react with 2.5 mol O2, we need 2.5×2=5 mol H2.
- Since we have exactly 5 mol H2, both are consumed completely.
- Mass of Water:
- 2.5 mol O2 yields 5 mol H2O.
- Mass=5 mol×18 g/mol=90 g.
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About This Question
- Subject
- chemistry
- Chapter
- some basic concepts in chemistry
- Topic
- limiting reagent
- Difficulty
- Medium
- Year
- 2025
Solution
Correct Answer:
90 g
- Equation: 2H2+O2→2H2O
- Moles calculation:
- Moles H2=10/2=5 mol.
- Moles O2=80/32=2.5 mol.
- Stoichiometry check:
- To react with 2.5 mol O2, we need 2.5×2=5 mol H2.
- Since we have exactly 5 mol H2, both are consumed completely.
- Mass of Water:
- 2.5 mol O2 yields 5 mol H2O.
- Mass=5 mol×18 g/mol=90 g.
This medium difficulty chemistry question is from the chapter some basic concepts in chemistry, covering the topic of limiting reagent. It appeared in the 2025 exam.
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