Limiting Reagent

Question

10 g of hydrogen reacts with 80 g of oxygen. What is the mass of water formed?

RankGuru · Accepted Answer

1. **Equation**: $2H_2 + O_2 	o 2H_2O$
2. **Moles calculation**:
   - $	ext{Moles } H_2 = 10/2 = 5 	ext{ mol}$.
   - $	ext{Moles } O_2 = 80/32 = 2.5 	ext{ mol}$.
3. **Stoichiometry check**:
   - To react with $2.5 	ext{ mol } O_2$, we need $2.5 	imes 2 = 5 	ext{ mol } H_2$.
   - Since we have exactly $5 	ext{ mol } H_2$, both are consumed completely.
4. **Mass of Water**:
   - $2.5 	ext{ mol } O_2$ yields $5 	ext{ mol } H_2O$.
   - $	ext{Mass} = 5 	ext{ mol} 	imes 18 	ext{ g/mol} = 90 	ext{ g}$.

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