limiting reagent

Question

Nitrogen and hydrogen react to form ammonia. If 28 g N₂ and 6 g H₂ are mixed, which is the limiting reagent?

RankGuru · Accepted Answer

1. **Balanced Equation**: $N_2 + 3H_2 	o 2NH_3$
2. **Moles present**:
   - $	ext{Moles } N_2 = 28/28 = 1 	ext{ mol}$.
   - $	ext{Moles } H_2 = 6/2 = 3 	ext{ mol}$.
3. **Compare with stoichiometric ratio**:
   - The reaction requires $N_2 : H_2$ in $1:3$ ratio.
   - The actual ratio present is $1:3$.
   - Result: Both reactants will be consumed completely; there is no limiting reagent.

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limiting reagent

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