Kinetic Energy
A body of mass 4 kg moving with a velocity of 10 m/s is brought to rest by a constant force in 5 seconds. What is the work done by the force?
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About This Question
- Subject
- physics
- Chapter
- work, energy and power
- Topic
- kinetic energy
- Difficulty
- Medium
- Year
- 2025
Solution
Correct Answer:
-200 J
- Work-Energy Theorem: The work done by all forces acting on a particle is equal to the change in its kinetic energy (W=ΔK).
- Initial Kinetic Energy (Ki):
- Ki=21mv2=21×4×(10)2=2×100=200 J.
- Final Kinetic Energy (Kf):
- Since it is brought to rest, Kf=0 J.
- Work Calculation:
- W=Kf−Ki=0−200=−200 J.
- Interpretation: The negative sign indicates that the force is doing work in a direction opposite to the displacement (resistive force).
This medium difficulty physics question is from the chapter work, energy and power, covering the topic of kinetic energy. It appeared in the 2025 exam.
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