Work Done By A Force At Right Angles
A satellite moves in a perfectly circular orbit around the Earth under the gravitational pull directed toward the centre. How much work does the gravitational force do on the satellite during one complete revolution?
Select the correct option:
Solution
Zero
As explained in NCERT Class 11, Chapter 6 (Work, Energy and Power), the work done by a force is W = F·d·cos(theta), and it vanishes whenever the force is perpendicular to the displacement. In a circular orbit the gravitational force always points toward the centre, while the satellite's velocity and hence its instantaneous displacement are always tangential, so the angle between them is 90 degrees and cos(90) = 0 at every instant. Therefore gravity does zero work throughout, and the satellite's speed and kinetic energy stay constant. The option about positive work equal to kinetic energy contradicts the constancy of speed. The option about negative work mislabels the situation. The option involving speed times circumference ignores the perpendicularity. A consistency check: since the orbital speed is constant, the work-energy theorem demands zero net work, fully agreeing with the geometric argument.
🔒 Solution Hidden from View
Submit your answer to unlock the detailed step-by-step solution.
About This Question
- Subject
- physics
- Chapter
- work, energy and power
- Topic
- work done by a force at right angles
- Difficulty
- Medium
- Year
- 2025
Solution
Correct Answer:
Zero
As explained in NCERT Class 11, Chapter 6 (Work, Energy and Power), the work done by a force is W = F·d·cos(theta), and it vanishes whenever the force is perpendicular to the displacement. In a circular orbit the gravitational force always points toward the centre, while the satellite's velocity and hence its instantaneous displacement are always tangential, so the angle between them is 90 degrees and cos(90) = 0 at every instant. Therefore gravity does zero work throughout, and the satellite's speed and kinetic energy stay constant. The option about positive work equal to kinetic energy contradicts the constancy of speed. The option about negative work mislabels the situation. The option involving speed times circumference ignores the perpendicularity. A consistency check: since the orbital speed is constant, the work-energy theorem demands zero net work, fully agreeing with the geometric argument.
This medium difficulty physics question is from the chapter work, energy and power, covering the topic of work done by a force at right angles. It appeared in the 2025 exam.
Looking for more practice? Explore all physics questions or browse work, energy and power questions on RankGuru.