Kinetic Energy
A 3 kg object speeds up from 4 m/s to 10 m/s. Change in kinetic energy?
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About This Question
- Subject
- physics
- Chapter
- work, energy and power
- Topic
- kinetic energy
- Difficulty
- Easy
- Year
- 2025
Solution
Correct Answer:
126 J
- Kinetic Energy Formula: K=21mv2.
- Change Calculation: ΔK=Kfinal−Kinitial=21mvf2−21mvi2.
- Data Substitution:
- Mass m=3 kg
- vi=4 m/s ⟹vi2=16
- vf=10 m/s ⟹vf2=100
- Calculate:
- ΔK=21×3×(100−16)
- ΔK=1.5×84=126 J.
- Result: The object gained 126 J of kinetic energy.
This easy difficulty physics question is from the chapter work, energy and power, covering the topic of kinetic energy. It appeared in the 2025 exam.
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