Skip to content

Dimensional Analysis

Easyphysics

The coefficient of viscosity of a fluid appears in Stokes' law for the drag on a small sphere; what is its dimensional formula?

Select the correct option:

🔒 Solution Hidden from View

Submit your answer to unlock the detailed step-by-step solution.

About This Question

Subject
physics
Chapter
physics and measurement
Topic
dimensional analysis
Difficulty
Easy
Year
2025
Tags
coefficient of viscositydimensional formulaStokes lawvelocity gradientfluid mechanics

Solution

Correct Answer:

Viscosity quantifies a fluid's internal resistance to flow and is defined through the tangential viscous force per unit area produced by a velocity gradient, F/A = η(dv/dx). Rearranging gives η = F / (A · dv/dx), so its dimensions follow directly from the dimensions of force, area and velocity gradient. Force has dimensions M L T^-2, area contributes L^2, and the velocity gradient dv/dx has dimensions (L T^-1)/L = T^-1. Combining these, η has dimensions (M L T^-2) / (L^2 · T^-1) = M L^-1 T^-1. The option M L T^-1 corresponds to linear momentum, not viscosity, so it is wrong. The option M L^-1 T^-2 is the dimension of pressure or stress and therefore cannot represent η. The option M L^2 T^-1 matches the dimension of angular momentum or the Planck constant and is unrelated. This treatment is identical to the NCERT derivation of the SI unit of viscosity, the poiseuille (Pa·s). A sanity check confirms consistency, since Pa·s = (N·m^-2)·s expands to M L^-1 T^-1.

This easy difficulty physics question is from the chapter physics and measurement, covering the topic of dimensional analysis. It appeared in the 2025 exam.

Looking for more practice? Explore all physics questions or browse physics and measurement questions on RankGuru.