Dimensional Analysis

Easyphysics

Velocity v = A t + B t^2. Dimensions of B are:

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$L T^{- 1}$

$L T^{- 2}$

$L T^{- 3}$

$M^{0}$

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About This Question

Subject: physics
Chapter: physics and measurement
Topic: dimensional analysis
Difficulty: Easy
Year: 2025

Solution

Correct Answer:

$L T^{- 3}$

According to the Principle of Homogeneity, the dimensions of each term in a physical equation must be the same.

$[v] = [L T^{- 1}]$
The term $[B t^{2}]$ must have the same dimensions as velocity: $[B] \cdot [T^{2}] = [L T^{- 1}]$ $[B] = \frac{[ L T ^{- 1} ]}{[ T ^{2} ]} = [L T^{- 3}]$ .

This easy difficulty physics question is from the chapter physics and measurement, covering the topic of dimensional analysis. It appeared in the 2025 exam.

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Dimensional Analysis

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