Dimensional Analysis

Question

Which combination has dimensions of pressure?

RankGuru · Accepted Answer

Standard dimensions for Pressure: $[ML^{-1} T^{-2}]$.
1. **Force/Area**: $[MLT^{-2}] / [L^2] = [ML^{-1} T^{-2}]$. (Correct)
2. **Energy/Volume**: $[ML^2 T^{-2}] / [L^3] = [ML^{-1} T^{-2}]$. (Correct)
3. **Momentum/(Area·Time)**: $[MLT^{-1}] / ([L^2] \cdot [T]) = [MLT^{-1}] / [L^2 T] = [ML^{-1} T^{-2}]$. (Correct)
All three physical interpretations lead to the same dimensions.

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