Compound And Multiple Angles
By repeatedly using the triple-angle identity, the exact value of sin3θ when sinθ=21 and θ is acute simplifies to which of the following numbers?
Select the correct option:
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About This Question
- Subject
- mathematics
- Chapter
- trigonometry
- Topic
- compound and multiple angles
- Difficulty
- Easy
- Year
- 2025
Solution
Correct Answer:
1
The controlling formula is the triple-angle identity sin3θ=3sinθ−4sin3θ, which expresses the sine of a tripled angle entirely in terms of the sine of the original angle. This identity is built by combining the angle-addition formula with the double-angle formulas, so it lets a tripled angle be evaluated algebraically without ever finding the angle itself. Substituting the given value sinθ=21 directly, the expression becomes 3⋅21−4⋅(21)3=23−4⋅81=23−21=1. The acute condition uniquely fixes θ=30∘, so the tripled angle is 90∘ and sin90∘=1, matching the algebraic result exactly. Option 23 confuses the answer with a cosine value. Option 21 simply repeats the original sine without applying the tripling. Option 0 misapplies the cubic term. This follows the standard triple-angle expansion pattern of JEE Advanced. As a final consistency check, the geometric route confirms that θ=30∘ gives 3θ=90∘ and hence sin3θ=1, in full agreement with the identity-based computation.
This easy difficulty mathematics question is from the chapter trigonometry, covering the topic of compound and multiple angles. It appeared in the 2025 exam.
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