Properties Of Triangles
In a triangle ABC the sides satisfy a=13, b=14, and c=15 units; using the cosine rule, the cosine of the angle opposite the side of length 14 equals which value?
Select the correct option:
Solution
6533
The cosine rule is the standard JEE Advanced tool for relating all three sides of a triangle to a single angle, generalizing the Pythagorean theorem to triangles that need not contain a right angle. The angle opposite the side b=14 is angle B, and the rule states cosB=2aca2+c2−b2, where the side opposite the target angle appears with a minus sign in the numerator. Substituting the squared sides a2=169, c2=225, and b2=196, the numerator becomes 169+225−196=198, while the denominator is 2⋅13⋅15=390. Dividing both numerator and denominator by their common factor six gives cosB=390198=6533. Option 135 corresponds to a different angle in the triangle and a mismatched ratio. Option 54 comes from misapplying the rule to the side a rather than b. Option 1312 mistakes a sine-type value for a cosine. This matches the canonical cosine-rule derivation used repeatedly in JEE Advanced triangle questions. As a final plausibility check, 6533≈0.508 is a legitimate positive cosine, indicating an acute angle, which is fully consistent with the well-known fact that the 13-14-15 triangle is acute.
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About This Question
- Subject
- mathematics
- Chapter
- trigonometry
- Topic
- properties of triangles
- Difficulty
- Medium
- Year
- 2025
Solution
Correct Answer:
6533
The cosine rule is the standard JEE Advanced tool for relating all three sides of a triangle to a single angle, generalizing the Pythagorean theorem to triangles that need not contain a right angle. The angle opposite the side b=14 is angle B, and the rule states cosB=2aca2+c2−b2, where the side opposite the target angle appears with a minus sign in the numerator. Substituting the squared sides a2=169, c2=225, and b2=196, the numerator becomes 169+225−196=198, while the denominator is 2⋅13⋅15=390. Dividing both numerator and denominator by their common factor six gives cosB=390198=6533. Option 135 corresponds to a different angle in the triangle and a mismatched ratio. Option 54 comes from misapplying the rule to the side a rather than b. Option 1312 mistakes a sine-type value for a cosine. This matches the canonical cosine-rule derivation used repeatedly in JEE Advanced triangle questions. As a final plausibility check, 6533≈0.508 is a legitimate positive cosine, indicating an acute angle, which is fully consistent with the well-known fact that the 13-14-15 triangle is acute.
This medium difficulty mathematics question is from the chapter trigonometry, covering the topic of properties of triangles. It appeared in the 2025 exam.
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