Properties Of Triangles
Applying the sine rule in a triangle where angle A=30∘, angle B=45∘, and the side a opposite A measures 10 units, the length of side b equals which value?
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About This Question
- Subject
- mathematics
- Chapter
- trigonometry
- Topic
- properties of triangles
- Difficulty
- Easy
- Year
- 2025
Solution
Correct Answer:
102
The governing relation is the law of sines, which states that in any triangle the ratio of each side to the sine of its opposite angle is constant, written sinAa=sinBb=sinCc. This proportionality lets an unknown side be recovered as soon as one matching side-angle pair and the second angle are known. Rearranging the relevant proportion for b gives b=sinAasinB. Substituting the standard values sinA=sin30∘=21 and sinB=sin45∘=22 along with a=10, we obtain b=2110⋅22=2152=102. Option 52 forgets to divide by sin30∘, halving the result. Option 20 incorrectly replaces sin45∘ with 1. Option 103 uses sin60∘ in place of sin45∘. This matches the canonical sine-rule application in JEE Advanced triangle problems. As a final plausibility check, the larger angle lies opposite the larger side, and since B=45∘>A=30∘, the side b must exceed a; indeed 102≈14.1>10, confirming the answer is geometrically consistent.
This easy difficulty mathematics question is from the chapter trigonometry, covering the topic of properties of triangles. It appeared in the 2025 exam.
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