Young's Modulus
A wire length 2 m, area 2×10⁻⁶ m², Young's modulus 2×10¹¹ Pa stretches 1 mm under load. Force applied?
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About This Question
- Subject
- physics
- Chapter
- properties of solids and liquids
- Topic
- young's modulus
- Difficulty
- Medium
- Year
- 2025
Solution
Correct Answer:
200 N
- Young's Modulus Formula: Y=StrainStress=ΔL/LF/A=AΔLFL.
- Isolate F: F=LYAΔL.
- Substitute Values:
- Y=2×1011 Pa
- A=2×10−6 m2
- ΔL=1 mm=10−3 m
- L=2 m
- Calculation:
- F=2(2×1011)(2×10−6)(10−3)
- F=24×1011−6−3
- F=2400=200 N.
- Conclusion: The applied force is 200 N.
This medium difficulty physics question is from the chapter properties of solids and liquids, covering the topic of young's modulus. It appeared in the 2025 exam.
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