Stefan-boltzmann Law Of Radiation
If the absolute temperature of a perfectly black body radiating heat is doubled, by what factor does the total power radiated per unit area from its surface increase?
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About This Question
- Subject
- physics
- Chapter
- properties of solids and liquids
- Topic
- stefan-boltzmann law of radiation
- Difficulty
- Hard
- Year
- 2025
Solution
Correct Answer:
Sixteen times
According to NCERT Class 11, Chapter 11 (Thermal Properties of Matter), the Stefan-Boltzmann law states that the energy radiated per unit area per unit time by a perfect black body is proportional to the fourth power of its absolute temperature, E=σT4, where σ is the Stefan constant. This strong dependence arises because hotter bodies emit far more thermal radiation across all wavelengths. Doubling the absolute temperature multiplies the radiated power per unit area by 24=16. The option 'four times' wrongly uses a square-law dependence. The option 'eight times' applies a cubic power. The option 'two times' assumes a simple linear relation, ignoring the fourth-power law. It is essential to use absolute (kelvin) temperature in this law, not Celsius, since the fourth power is meaningful only on the absolute scale where zero corresponds to no thermal radiation. As a plausibility check, this steep rise explains why a modest increase in a filament's temperature causes a dramatic jump in radiated energy and brightness, and why hot blue stars of higher surface temperature are vastly more luminous than cooler red stars of the same size. The sixteen-fold increase from merely doubling the temperature is exactly the dramatic sensitivity that the fourth-power law predicts, confirming the answer.
This hard difficulty physics question is from the chapter properties of solids and liquids, covering the topic of stefan-boltzmann law of radiation. It appeared in the 2025 exam.
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