Work done ($W$) by a constant force is the dot product of the force vector and the displacement vector: $W=\vec{F}\cdot \vec{d}=F\cdot d\cos \theta$ Given:

• $F=10\text{ N}$
• $d=6\text{ m}$
• Since the force acts along the displacement, the angle $\theta =0^{\circ }$ and $\cos 0^{\circ }=1$. $W=10\times 6\times 1=60\text{ Joules}$.