Work By Constant Force
Easyphysics
A constant horizontal force of 25 N moves a crate 6 m on a frictionless floor. Work done?
Select the correct option:
Solution
Incorrect! Answer:
150 J
- Definition of Work: Work is defined as the dot product of the force vector and the displacement vector (W=F⋅d).
- Magnitude form: W=Fdcosθ, where θ is the angle between force and displacement.
- Identify Variables:
- Force F=25 N
- Displacement d=6 m
- Direction: Since the force is horizontal and the crate moves on a floor, we assume θ=0∘⟹cos0∘=1.
- Calculation:
- W=25×6×1=150 J.
- Conclusion: The total work done by the force is 150 J.
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About This Question
- Subject
- physics
- Chapter
- work, energy and power
- Topic
- work by constant force
- Difficulty
- Easy
- Year
- 2025
Solution
Correct Answer:
150 J
- Definition of Work: Work is defined as the dot product of the force vector and the displacement vector (W=F⋅d).
- Magnitude form: W=Fdcosθ, where θ is the angle between force and displacement.
- Identify Variables:
- Force F=25 N
- Displacement d=6 m
- Direction: Since the force is horizontal and the crate moves on a floor, we assume θ=0∘⟹cos0∘=1.
- Calculation:
- W=25×6×1=150 J.
- Conclusion: The total work done by the force is 150 J.
This easy difficulty physics question is from the chapter work, energy and power, covering the topic of work by constant force. It appeared in the 2025 exam.
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