Vsepr & Hybridisation
Which set lists increasing bond length for the carbon–oxygen bonds?
Select the correct option:
Solution
C=O (ketone) < C=O (amide) < C–O (alcohol)
- Bond Order Link: Bond length is inversely proportional to bond order.
- Analysis of Bonds:
- C=O (Ketone): A nearly pure double bond (BO≈2). Shortest.
- C=O (Amide): The Nitrogen lone pair delocalizes into the carbonyl (O−C=N↔O−−C=N+). This resonance gives the C−O bond partial single bond character, increasing its length compared to ketones.
- C-O (Alcohol): A standard single bond (BO=1). Longest.
- Comparison: Single>Partial Double>Double.
- Result: Ketone < Amide < Alcohol.
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About This Question
- Subject
- chemistry
- Chapter
- chemical bonding and molecular structure
- Topic
- vsepr & hybridisation
- Difficulty
- Hard
- Year
- 2025
Solution
Correct Answer:
C=O (ketone) < C=O (amide) < C–O (alcohol)
- Bond Order Link: Bond length is inversely proportional to bond order.
- Analysis of Bonds:
- C=O (Ketone): A nearly pure double bond (BO≈2). Shortest.
- C=O (Amide): The Nitrogen lone pair delocalizes into the carbonyl (O−C=N↔O−−C=N+). This resonance gives the C−O bond partial single bond character, increasing its length compared to ketones.
- C-O (Alcohol): A standard single bond (BO=1). Longest.
- Comparison: Single>Partial Double>Double.
- Result: Ketone < Amide < Alcohol.
This hard difficulty chemistry question is from the chapter chemical bonding and molecular structure, covering the topic of vsepr & hybridisation. It appeared in the 2025 exam.
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