van't hoff factor

Question

The Van't Hoff factor (i) for NaCl in dilute aqueous solution is approximately:

RankGuru · Accepted Answer

The **Van't Hoff Factor ($i$)** accounts for the degree of association or dissociation of a solute.
- Formula for complete dissociation: $i = 	ext{number of particles after dissociation}$.
- For **NaCl** (an electrolyte): $NaCl 	o Na^+ + Cl^-$
- Since $1$ mole of $NaCl$ yields $2$ moles of ions, for a dilute solution where dissociation is considered complete, **$i \approx 2$**. This value is used to calculate the 'effective' concentration of particles for colligative properties.

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More van't hoff factor Practice Questions

Which solute has van't Hoff factor i ≈ 3 in dilute aqueous solution?