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Van't Hoff Factor

Mediumchemistry

A 0.1 m aqueous solution of BaCl₂ shows a depression of freezing point of 0.480 K. If Kf for water is 1.86 K kg mol⁻¹, the van't Hoff factor (i) for BaCl₂ in this solution is:

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About This Question

Subject
chemistry
Chapter
solutions
Topic
van't hoff factor
Difficulty
Medium
Year
2025
Tags
Van't Hoff FactorElectrolyteFreezing Point Depression

Solution

Correct Answer:

The observed freezing point depression is ΔTf = i × Kf × m. Substituting: 0.480 = i × 1.86 × 0.1 = i × 0.186. Therefore, i = 0.480 / 0.186 = 2.58. For complete dissociation of BaCl₂ → Ba²⁺ + 2Cl⁻, the theoretical van't Hoff factor would be 3 (one formula unit yields 3 ions). The observed value of 2.58 is less than 3, indicating incomplete dissociation or ion-pair formation in the solution. This is typical behaviour for strong electrolytes at moderate concentrations where interionic attractions reduce the effective number of particles.

This medium difficulty chemistry question is from the chapter solutions, covering the topic of van't hoff factor. It appeared in the 2025 exam.

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