Valence Bond Theory And Resonance
The resonance structures of SO_3 contribute to delocalisation of pi electrons; what is the formal charge on sulfur in the most stable Lewis structure of SO_3?
Select the correct option:
Solution
+2
Formal charge is calculated using the formula: Formal Charge = (Valence electrons) - (Non-bonding electrons) - (1/2)(Bonding electrons). In the most basic Lewis structure of SO_3, sulfur forms double bonds with two oxygen atoms and a single bond with the third. Sulfur has 6 valence electrons. If sulfur forms one double bond and two single bonds (with complete octets on all oxygens), sulfur has 0 non-bonding electrons and shares 8 bonding electrons (2 double bond + 2 single bond pairs = not quite). Let us be precise: in a structure where S has two double bonds and one single bond, S uses 10 electrons in bonding (five pairs) with no lone pairs. Formal charge on S = 6 - 0 - (10/2) = 6 - 5 = +1. However, in the simplest structure with all single bonds and a positive charge, or with resonance involving S=O bonds, the formal charge on S varies. In the Lewis structure with three S=O double bonds (expanded octet), formal charge = 6 - 0 - 6 = 0, but this requires 12 electrons around S. In the most commonly drawn single-resonance structure with one double bond and two coordinate/dative bonds from S to O (S^+ to O^-), formal charge on S = 6 - 0 - (8/2) = +2. This is the textbook answer for the un-expanded octet structure. Option +1 applies when S forms two double bonds. Option 0 applies in the expanded-octet structure. Option -1 is not a correct formal charge for sulfur in SO_3. This is a standard NCERT/JEE concept on formal charge and resonance. Plausibility: SO_3 is a known electrophile, consistent with positive formal charge on S in the basic Lewis structure.
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About This Question
- Subject
- chemistry
- Chapter
- chemical bonding and molecular structure
- Topic
- valence bond theory and resonance
- Difficulty
- Hard
- Year
- 2025
Solution
Correct Answer:
+2
Formal charge is calculated using the formula: Formal Charge = (Valence electrons) - (Non-bonding electrons) - (1/2)(Bonding electrons). In the most basic Lewis structure of SO_3, sulfur forms double bonds with two oxygen atoms and a single bond with the third. Sulfur has 6 valence electrons. If sulfur forms one double bond and two single bonds (with complete octets on all oxygens), sulfur has 0 non-bonding electrons and shares 8 bonding electrons (2 double bond + 2 single bond pairs = not quite). Let us be precise: in a structure where S has two double bonds and one single bond, S uses 10 electrons in bonding (five pairs) with no lone pairs. Formal charge on S = 6 - 0 - (10/2) = 6 - 5 = +1. However, in the simplest structure with all single bonds and a positive charge, or with resonance involving S=O bonds, the formal charge on S varies. In the Lewis structure with three S=O double bonds (expanded octet), formal charge = 6 - 0 - 6 = 0, but this requires 12 electrons around S. In the most commonly drawn single-resonance structure with one double bond and two coordinate/dative bonds from S to O (S^+ to O^-), formal charge on S = 6 - 0 - (8/2) = +2. This is the textbook answer for the un-expanded octet structure. Option +1 applies when S forms two double bonds. Option 0 applies in the expanded-octet structure. Option -1 is not a correct formal charge for sulfur in SO_3. This is a standard NCERT/JEE concept on formal charge and resonance. Plausibility: SO_3 is a known electrophile, consistent with positive formal charge on S in the basic Lewis structure.
This hard difficulty chemistry question is from the chapter chemical bonding and molecular structure, covering the topic of valence bond theory and resonance. It appeared in the 2025 exam.
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