Uniform Acceleration (suvat)

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A particle starts from rest and accelerates uniformly at 3 m/s². Distance covered in 6 s?

RankGuru · Accepted Answer

1. **Identify Givens**:
   - Initial velocity ($u$) $= 0$ (starts from rest)
   - Acceleration ($a$) $= 3 	ext{ m/s}^2$
   - Time ($t$) $= 6$ s
2. **Choose Kinematic Equation**: For distance $s$, use $s = ut + \frac{1}{2} a t^2$.
3. **Calculation**:
   - $s = (0 	imes 6) + \frac{1}{2} (3) (6^2)$
   - $s = 0 + 1.5 	imes 36$
   - $s = 54$ m.
4. **Result**: The particle covers **$54$ m** in $6$ seconds.

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Uniform Acceleration (suvat)

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