Velocity-time Graph
On a velocity-time graph, a body moves with velocity increasing uniformly from 5 m/s to 25 m/s over 4 seconds, what distance does it cover in this interval?
Select the correct option:
🔒 Solution Hidden from View
Submit your answer to unlock the detailed step-by-step solution.
More kinematics Practice Questions
The velocity-time graph for a particle starting from rest is a straight line. If the particle travel...
The velocity-time graph for a particle starting from rest is a straight line. If the particle travel...
A body starting from rest moves with uniform acceleration of 6 m/s² along a straight road, what dist...
A body starting from rest moves with uniform acceleration of 6 m/s² along a straight road, what dist...
A swimmer who can swim at 4 m/s in still water heads straight across a river flowing at 3 m/s, what ...
A swimmer who can swim at 4 m/s in still water heads straight across a river flowing at 3 m/s, what ...
Among the following physical quantities encountered in motion, which one is correctly classified as ...
Among the following physical quantities encountered in motion, which one is correctly classified as ...
A particle moves 8 m east and then 6 m north in a total time of 5 seconds along a flat surface, what...
A particle moves 8 m east and then 6 m north in a total time of 5 seconds along a flat surface, what...
A particle is said to be in uniform motion along a straight line when which of the following conditi...
A particle is said to be in uniform motion along a straight line when which of the following conditi...
The position of a particle along a straight line varies with time as x equals 2t cubed minus 3t squa...
The position of a particle along a straight line varies with time as x equals 2t cubed minus 3t squa...
From the top of a building a ball is dropped just as another ball is thrown up from the ground at 25...
From the top of a building a ball is dropped just as another ball is thrown up from the ground at 25...
A ball thrown vertically upward with an initial speed of 20 m/s reaches its highest point, taking g ...
A ball thrown vertically upward with an initial speed of 20 m/s reaches its highest point, taking g ...
A javelin is launched at 40 m/s at 45 degrees to the horizontal across a level field, with g equal t...
A javelin is launched at 40 m/s at 45 degrees to the horizontal across a level field, with g equal t...
A motorcyclist moving at 30 m/s applies brakes and decelerates uniformly at 5 m/s², how far does the...
A motorcyclist moving at 30 m/s applies brakes and decelerates uniformly at 5 m/s², how far does the...
The slope of a position-time graph at any instant for a moving particle physically represents which ...
The slope of a position-time graph at any instant for a moving particle physically represents which ...
About This Question
- Subject
- physics
- Chapter
- kinematics
- Topic
- velocity-time graph
- Difficulty
- Medium
- Year
- 2025
Solution
Correct Answer:
60 m
As taught in NCERT Class 11, Chapter 3 (Motion in a Straight Line), the area under a velocity-time graph equals the displacement of the body. For uniformly increasing velocity, the graph is a straight line forming a trapezium with the time axis. The area of this trapezium is the average of the two parallel velocity values times the time interval: distance = ((5 + 25)/2) × 4 = 15 × 4 = 60 m. The option 100 m wrongly uses the final velocity 25 m/s times 4 s, ignoring that velocity was lower earlier. The option 40 m uses only the initial velocity contribution incorrectly. The option 80 m results from using a wrong average of 20 m/s. Plausibility check: the constant acceleration is (25−5)/4 = 5 m/s², and substituting into s = ut + (1/2)at² gives 5×4 + (1/2)(5)(16) = 20 + 40 = 60 m, exactly matching the graphical area and confirming the result.
This medium difficulty physics question is from the chapter kinematics, covering the topic of velocity-time graph. It appeared in the 2025 exam.
Looking for more practice? Explore all physics questions or browse kinematics questions on RankGuru.