Stopping Potential And Maximum Kinetic Energy
During a photoelectric experiment the reverse voltage at which the photocurrent just becomes zero is recorded as 1.5 V. What is the maximum kinetic energy of the emitted photoelectrons in electron-volts?
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About This Question
- Subject
- physics
- Chapter
- dual nature of radiation and matter
- Topic
- stopping potential and maximum kinetic energy
- Difficulty
- Easy
- Year
- 2025
Solution
Correct Answer:
1.5 eV
The stopping potential V0 is the minimum negative voltage on the collector that turns back even the fastest photoelectrons, reducing the photocurrent to zero. At this point the work done by the retarding field on an electron exactly equals the electron's maximum kinetic energy, so eV0=Kmax. Expressed in electron-volts, the maximum kinetic energy is numerically equal to the stopping potential in volts, because one electron-volt is by definition the energy gained by one electronic charge moving through one volt. Hence Kmax=1.5 eV. The value 3.0 eV wrongly doubles the result. The value 0.75 eV halves it. The value 2.4×10−19 eV confuses joules with electron-volts, since 1.5 eV=2.4×10−19 J, not eV. This direct correspondence between stopping potential and electron energy is a cornerstone of the photoelectric measurements described in NCERT. As a unit check, the eV scale keeps numbers convenient and confirms the answer's consistency.
This easy difficulty physics question is from the chapter dual nature of radiation and matter, covering the topic of stopping potential and maximum kinetic energy. It appeared in the 2025 exam.
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