Stopping Potential From Incident Wavelength
Monochromatic radiation of wavelength 248 nm falls on a photosensitive cathode whose work function is 2.0 eV. What reverse potential must the anode reach to completely stop the emitted photoelectrons?
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About This Question
- Subject
- physics
- Chapter
- dual nature of radiation and matter
- Topic
- stopping potential from incident wavelength
- Difficulty
- Medium
- Year
- 2025
Solution
Correct Answer:
3.0 V
The stopping potential satisfies eV0=Kmax=λhc−ϕ0, so dividing the maximum kinetic energy by the electronic charge gives the voltage needed to halt the fastest electrons. First find the photon energy: 2481240=5.0 eV using hc=1240 eV nm. The maximum kinetic energy is then 5.0−2.0=3.0 eV, and since Kmax in eV equals V0 in volts, V0=3.0 V. The option 5.0 V mistakes the photon energy for the stopping potential. The option 2.0 V confuses the work function with Kmax. The option 1.0 V wrongly halves the kinetic energy. This relation lets experimenters extract work functions directly from stopping-potential measurements, a standard technique highlighted in the NCERT discussion of Millikan's verification. A quick check confirms V0 is positive and smaller than the full photon energy in volts, as it must be once the work function is paid. A useful corollary is that if the same metal were illuminated with longer-wavelength light, the photon energy would drop, the maximum kinetic energy would shrink, and the required stopping potential would fall accordingly, vanishing entirely once the threshold wavelength is reached. This direct link between wavelength and stopping voltage allows the work function of an unknown cathode to be deduced from a single careful measurement, a technique widely used in surface physics.
This medium difficulty physics question is from the chapter dual nature of radiation and matter, covering the topic of stopping potential from incident wavelength. It appeared in the 2025 exam.
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