Stoichiometry

Question

What mass of oxygen is required for complete combustion of 2.2 g of propane (C₃H₈)?

RankGuru · Accepted Answer

1. **Write balanced equation**:
   - $C_3H_8 + 5O_2 	o 3CO_2 + 4H_2O$
2. **Moles of Propane ($C_3H_8$)**:
   - Molar mass $= 3(12) + 8(1) = 44 	ext{ g/mol}$.
   - $	ext{Moles} = \frac{2.2 	ext{ g}}{44 	ext{ g/mol}} = 0.05 	ext{ mol}$.
3. **Moles of $O_2$ Required**:
   - 1 mole propane requires 5 moles $O_2$.
   - $	ext{Moles } O_2 = 0.05 	imes 5 = 0.25 	ext{ mol}$.
4. **Calculate Mass of $O_2$**:
   - $	ext{Mass} = 0.25 	ext{ mol} 	imes 32 	ext{ g/mol} = 8 	ext{ g}$.

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