Stoichiometry
What mass of oxygen is required for complete combustion of 2.2 g of propane (C₃H₈)?
Select the correct option:
Solution
8 g
- Write balanced equation:
- C3H8+5O2→3CO2+4H2O
- Moles of Propane (C3H8):
- Molar mass =3(12)+8(1)=44 g/mol.
- Moles=44 g/mol2.2 g=0.05 mol.
- Moles of O2 Required:
- 1 mole propane requires 5 moles O2.
- Moles O2=0.05×5=0.25 mol.
- Calculate Mass of O2:
- Mass=0.25 mol×32 g/mol=8 g.
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About This Question
- Subject
- chemistry
- Chapter
- some basic concepts in chemistry
- Topic
- stoichiometry
- Difficulty
- Medium
- Year
- 2025
Solution
Correct Answer:
8 g
- Write balanced equation:
- C3H8+5O2→3CO2+4H2O
- Moles of Propane (C3H8):
- Molar mass =3(12)+8(1)=44 g/mol.
- Moles=44 g/mol2.2 g=0.05 mol.
- Moles of O2 Required:
- 1 mole propane requires 5 moles O2.
- Moles O2=0.05×5=0.25 mol.
- Calculate Mass of O2:
- Mass=0.25 mol×32 g/mol=8 g.
This medium difficulty chemistry question is from the chapter some basic concepts in chemistry, covering the topic of stoichiometry. It appeared in the 2025 exam.
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