Stoichiometry

Question

When 10.6 g of Na₂CO₃ reacts completely with excess HCl, what volume of CO₂ gas is produced at STP?

RankGuru · Accepted Answer

1. **Write the balanced equation**:
   - $Na_2CO_3 + 2HCl 	o 2NaCl + H_2O + CO_2$
2. **Find Moles of $Na_2CO_3$**:
   - Molar mass of $Na_2CO_3 = 2(23) + 12 + 3(16) = 106 	ext{ g/mol}$.
   - $	ext{Moles} = \frac{10.6 	ext{ g}}{106 	ext{ g/mol}} = 0.1 	ext{ mol}$.
3. **Stoichiometry**:
   - $1 	ext{ mole } Na_2CO_3 	o 1 	ext{ mole } CO_2$.
   - Thus, $0.1 	ext{ mole of } CO_2$ is produced.
4. **Calculate Volume at STP**:
   - $	ext{Volume} = 	ext{moles} 	imes 22.4 	ext{ L}$
   - $	ext{Volume} = 0.1 	imes 22.4 = 2.24 	ext{ L}$.

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