Stoichiometry
Mediumchemistry
When 10.6 g of Na₂CO₃ reacts completely with excess HCl, what volume of CO₂ gas is produced at STP?
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Solution
Incorrect! Answer:
2.24 L
- Write the balanced equation:
- Na2CO3+2HCl→2NaCl+H2O+CO2
- Find Moles of Na2CO3:
- Molar mass of Na2CO3=2(23)+12+3(16)=106 g/mol.
- Moles=106 g/mol10.6 g=0.1 mol.
- Stoichiometry:
- 1 mole Na2CO3→1 mole CO2.
- Thus, 0.1 mole of CO2 is produced.
- Calculate Volume at STP:
- Volume=moles×22.4 L
- Volume=0.1×22.4=2.24 L.
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About This Question
- Subject
- chemistry
- Chapter
- some basic concepts in chemistry
- Topic
- stoichiometry
- Difficulty
- Medium
- Year
- 2025
This medium difficulty chemistry question is from the chapter some basic concepts in chemistry, covering the topic of stoichiometry. It appeared in the 2025 exam. Practice this and similar questions to strengthen your understanding of some basic concepts in chemistry concepts.
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