Spring Potential Energy

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A spring (k = 400 N/m) compressed by 0.15 m stores what energy?

RankGuru · Accepted Answer

1. **Elastic Potential Energy**: Energy stored in a spring due to deformation is $U = \frac{1}{2} k x^2$.
2. **Identify Variables**:
   - Spring constant $k = 400$ N/m
   - Displacement $x = 0.15$ m
3. **Calculation**:
   - $U = \frac{1}{2} 	imes 400 	imes (0.15)^2$
   - $U = 200 	imes 0.0225$
   - $U = 4.5$ J.
4. **Conclusion**: The stored energy is **$4.5$ J**.

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