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Speed Of Electromagnetic Waves

Easyphysics

A student derives the speed of light in vacuum from fundamental constants and needs the correct combination of permittivity and permeability.

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About This Question

Subject
physics
Chapter
electromagnetic waves
Topic
speed of electromagnetic waves
Difficulty
Easy
Year
2025
Tags
speed of lightpermittivity of free spacepermeability of free spaceMaxwell relationwave velocity

Solution

Correct Answer:

According to NCERT Class 12, Chapter 8 (Electromagnetic Waves), Maxwell's equations predict that electromagnetic disturbances travel through vacuum at a speed determined solely by the electric and magnetic properties of free space. The speed is expressed as c = 1 / √(μ₀ε₀), where μ₀ is the permeability and ε₀ is the permittivity of free space. Substituting μ₀ = 4π × 10⁻⁷ T·m/A and ε₀ = 8.85 × 10⁻¹² C²/N·m² yields approximately 3 × 10⁸ m/s, matching the measured speed of light — a triumph that showed light itself is an electromagnetic wave. The option c = μ₀ε₀ is dimensionally the inverse of speed squared, so it cannot represent a velocity. The form c = 1/(μ₀ε₀) has units of speed squared rather than speed, making it incorrect. The expression c = √(μ₀ε₀) gives the reciprocal of speed and is therefore dimensionally wrong. A dimensional check confirms that only 1/√(μ₀ε₀) yields metres per second, validating the correct choice.

This easy difficulty physics question is from the chapter electromagnetic waves, covering the topic of speed of electromagnetic waves. It appeared in the 2025 exam.

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