Displacement Current Calculation
The electric flux through a certain surface changes at a steady rate of 2.0 × 10⁴ V·m per second, and a student calculates the displacement current.
Select the correct option:
Solution
1.77 × 10⁻⁷ A
Drawing on NCERT Class 12, Chapter 8 (Electromagnetic Waves), the displacement current is defined by I_d = ε₀ (dΦ_E/dt), where ε₀ = 8.85 × 10⁻¹² C²/N·m² and dΦ_E/dt is the rate of change of electric flux through the chosen surface. This quantity arises purely from a time-varying electric field and behaves exactly like a real current in producing a magnetic field, which is why Maxwell could treat conduction and displacement currents on the same footing. The definition also explains why a steady, unchanging field gives zero displacement current: only a changing flux contributes. Substituting the given rate: I_d = 8.85 × 10⁻¹² × 2.0 × 10⁴ = 1.77 × 10⁻⁷ A. The value 8.85 × 10⁻⁸ A wrongly uses half the flux rate or omits the factor of two, giving an incorrect result. The value 2.26 × 10⁶ A is absurd because it divides by ε₀ rather than multiplying, inflating the current enormously. The value 4.43 × 10⁻⁹ A results from a power-of-ten mistake in handling the flux rate. A magnitude check confirms that such a modest flux change produces only a tiny sub-microampere displacement current, consistent with the selected value.
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About This Question
- Subject
- physics
- Chapter
- electromagnetic waves
- Topic
- displacement current calculation
- Difficulty
- Medium
- Year
- 2025
Solution
Correct Answer:
1.77 × 10⁻⁷ A
Drawing on NCERT Class 12, Chapter 8 (Electromagnetic Waves), the displacement current is defined by I_d = ε₀ (dΦ_E/dt), where ε₀ = 8.85 × 10⁻¹² C²/N·m² and dΦ_E/dt is the rate of change of electric flux through the chosen surface. This quantity arises purely from a time-varying electric field and behaves exactly like a real current in producing a magnetic field, which is why Maxwell could treat conduction and displacement currents on the same footing. The definition also explains why a steady, unchanging field gives zero displacement current: only a changing flux contributes. Substituting the given rate: I_d = 8.85 × 10⁻¹² × 2.0 × 10⁴ = 1.77 × 10⁻⁷ A. The value 8.85 × 10⁻⁸ A wrongly uses half the flux rate or omits the factor of two, giving an incorrect result. The value 2.26 × 10⁶ A is absurd because it divides by ε₀ rather than multiplying, inflating the current enormously. The value 4.43 × 10⁻⁹ A results from a power-of-ten mistake in handling the flux rate. A magnitude check confirms that such a modest flux change produces only a tiny sub-microampere displacement current, consistent with the selected value.
This medium difficulty physics question is from the chapter electromagnetic waves, covering the topic of displacement current calculation. It appeared in the 2025 exam.
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