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Single Slit Diffraction

Hardphysics

Monochromatic light of wavelength 500 nm passes through a single slit of width 0.1 mm, so what is the angular position of the first diffraction minimum?

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About This Question

Subject
physics
Chapter
optics
Topic
single slit diffraction
Difficulty
Hard
Year
2025
Tags
single slit diffractionfirst minimumslit widthsmall angle approximationdiffraction condition

Solution

Correct Answer:

Approximately 0.005 radian

In single slit diffraction, NCERT gives the condition for the dark fringes as , where is the slit width, the wavelength, and the order of the minimum. For the first minimum , and for small angles , so . Substituting m and m gives radian, or 0.005 radian. The value 0.05 radian is wrong because it misplaces the slit-width exponent by one order. The value 0.0025 radian is wrong because it halves the correct result, perhaps confusing the central maximum half-width incorrectly. The value 0.5 radian is wrong because it is far too large for such a narrow-wavelength-to-width ratio. As stated in NCERT Class 12, Chapter 10, the central maximum broadens as the slit narrows, since scales as . A magnitude check confirms that a slit two hundred times wider than the wavelength gives a small angle of a few milliradians, consistent with 0.005 radian.

This hard difficulty physics question is from the chapter optics, covering the topic of single slit diffraction. It appeared in the 2025 exam.

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