Single Slit Diffraction Minima
Condition for first minimum (m=1) in single slit diffraction (slit width a)?
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About This Question
- Subject
- physics
- Chapter
- optics
- Topic
- single slit diffraction minima
- Difficulty
- Hard
- Year
- 2025
Solution
Correct Answer:
a sinθ = λ
- Diffraction Logic: In a single slit of width a, the secondary wavelets from different parts of the slit interfere.
- Destructive Interference: Dark fringes (minima) occur when the path difference between waves from the top and bottom of the slit is an integer multiple of λ.
- General Formula: asinθ=mλ, where m=1,2,3,….
- Application: For the first minimum, we set m=1.
- Result: The condition is asinθ=λ. Note that m=1 for diffraction minima corresponds to m=1 for interference maxima in YDSE (different physics processes).
This hard difficulty physics question is from the chapter optics, covering the topic of single slit diffraction minima. It appeared in the 2025 exam.
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