Single Slit Diffraction Minima
Hardphysics
Condition for first minimum (m=1) in single slit diffraction (slit width a)?
Select the correct option:
Solution
Incorrect! Answer:
a sinθ = λ
- Diffraction Logic: In a single slit of width a, the secondary wavelets from different parts of the slit interfere.
- Destructive Interference: Dark fringes (minima) occur when the path difference between waves from the top and bottom of the slit is an integer multiple of λ.
- General Formula: asinθ=mλ, where m=1,2,3,….
- Application: For the first minimum, we set m=1.
- Result: The condition is asinθ=λ. Note that m=1 for diffraction minima corresponds to m=1 for interference maxima in YDSE (different physics processes).
🔒 Solution Hidden from View
Submit your answer to unlock the detailed step-by-step solution.
About This Question
- Subject
- physics
- Chapter
- optics
- Topic
- single slit diffraction minima
- Difficulty
- Hard
- Year
- 2025
This hard difficulty physics question is from the chapter optics, covering the topic of single slit diffraction minima. It appeared in the 2025 exam. Practice this and similar questions to strengthen your understanding of optics concepts.
Looking for more practice? Explore all physics questions or browse optics questions on RankGuru.