Sandmeyer Reaction
Mediumchemistry
Sandmeyer reaction converts anilines to aryl bromides via intermediate:
Select the correct option:
Solution
Incorrect! Answer:
Aryldiazonium salt
- Step 1 (Diazotization): Aniline is treated with nitrous acid (NaNO2+HCl) at 0–5∘C to form the benzene diazonium chloride (C6H5N2+Cl−).
- Step 2 (Sandmeyer): The stable diazonium salt is then treated with freshly prepared cuprous bromide (Cu2Br2) in HBr.
- Mechanism: The diazonium group is replaced by the Bromine atom, releasing Nitrogen gas (N2).
- Result: Aniline is converted to Bromobenzene via the aryldiazonium salt intermediate.
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About This Question
- Subject
- chemistry
- Chapter
- halogen organics
- Topic
- sandmeyer reaction
- Difficulty
- Medium
- Year
- 2025
Solution
Correct Answer:
Aryldiazonium salt
- Step 1 (Diazotization): Aniline is treated with nitrous acid (NaNO2+HCl) at 0–5∘C to form the benzene diazonium chloride (C6H5N2+Cl−).
- Step 2 (Sandmeyer): The stable diazonium salt is then treated with freshly prepared cuprous bromide (Cu2Br2) in HBr.
- Mechanism: The diazonium group is replaced by the Bromine atom, releasing Nitrogen gas (N2).
- Result: Aniline is converted to Bromobenzene via the aryldiazonium salt intermediate.
This medium difficulty chemistry question is from the chapter halogen organics, covering the topic of sandmeyer reaction. It appeared in the 2025 exam.
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