sandmeyer reaction

Question

Sandmeyer reaction converts anilines to aryl bromides via intermediate:

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1. **Step 1 (Diazotization)**: Aniline is treated with nitrous acid ($NaNO_2 + HCl$) at $0–5^\circ C$ to form the **benzene diazonium chloride** ($C_6H_5N_2^+Cl^-$).
2. **Step 2 (Sandmeyer)**: The stable diazonium salt is then treated with freshly prepared cuprous bromide ($Cu_2Br_2$) in $HBr$.
3. **Mechanism**: The diazonium group is replaced by the Bromine atom, releasing Nitrogen gas ($N_2$).
4. **Result**: Aniline is converted to Bromobenzene via the **aryldiazonium salt** intermediate.

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